I will surel mark your answer as brainliest....
QFactorize:
(a) 8(3a-2b)²-10(3a-2b)
(b) x³+2x²+5x+10
(c) 8-4a-2a²+a^4
Answers
Answered by
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(a)
8(3a - 2b)^2 - 10(3a - 2b)
= > (3a - 2b)(8(3a - 2b) - 10)
= > (3a - 2b)(24a - 16b - 10)
= > (3a - 2b)[2(12a - 8b - 5]
= > 2(3a - 2b)(12a - 8b - 5).
(2)
x^3 + 2x^2 + 5x + 10
= > x^3 + 2x^2 + 5x + 10
= > x^2(x + 2) + 5(x + 2)
= > (x^2 + 5)(x + 2)
(3)
8 - 4a - 2a^3 + a^4
= > (a^4 - 2a^3) + (-4a + 8)
= > a^3(a - 2) - 4(a - 2)
= > (a^3 - 4)(a - 2)
Hope this helps!
8(3a - 2b)^2 - 10(3a - 2b)
= > (3a - 2b)(8(3a - 2b) - 10)
= > (3a - 2b)(24a - 16b - 10)
= > (3a - 2b)[2(12a - 8b - 5]
= > 2(3a - 2b)(12a - 8b - 5).
(2)
x^3 + 2x^2 + 5x + 10
= > x^3 + 2x^2 + 5x + 10
= > x^2(x + 2) + 5(x + 2)
= > (x^2 + 5)(x + 2)
(3)
8 - 4a - 2a^3 + a^4
= > (a^4 - 2a^3) + (-4a + 8)
= > a^3(a - 2) - 4(a - 2)
= > (a^3 - 4)(a - 2)
Hope this helps!
DaIncredible:
amazing bhai ^_^
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