Question

i will surely follow you if you give the correct ans
refer to attachment ​

Answer 1

Step-by-step explanation:

I am using p in place of theta

given

sinp + sin^2p = 1

this gives

sinp= 1 - sin^2p

sinp= cos^2p

now

cos^12p+3cos^10p+3cos^8p+ cos^6p +cos^4p + 3cos^2p+2sin^2p

= (cos^4p)^3+3(cos^4p)^2*cos^2p + 3cos^4p"(cos^2p)^2+(cos^2p)^3+cos^4p+ 3cos^2p+2sin^2p

=(cos^4p +cos^2p)^3 + cos^4p + 3cos^2p +2 sin^2p

=(sin^2p+cos^2p)^3 + cos^4p+3cos^2p+2sin^2p

= 1 +( cos^2p)^2+3cos^2p+2sin^2p

= 1+sin^2p + 3cos^2p + 2sin^2p

=1 + 3sin^2p + 3cos^2p

= 1 + 3(sin^2p + cos^2p)

= 1 + 3

= 4