Math, asked by abhijay1705, 10 months ago

I will surely mark you as brainliest . Solve the following equations by given methods :

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Answers

Answered by naman2156
0

b)(i)

3x+2y=4

2y=4-3x

y=(4-3x)/2

2x-3y=7

2x-3((4-3x)/2)=7

2x-(12+9x)/2=7

2x-12/2+9x/2=7

2x+9x/2-6=7

(4x+9x)/2=7+6

13x/2=13

13x=26

x=26/13

x=2

2x-3y=7

2(2)-3y=7

4-3y=7

-3y=7-4

-3y=3

y=3/-3

y= -1

hence,x=2 and y= -1

(ii)

x-y+1=0

x-y= -1

-y= -1-x

-y= -(1+x)

y=1+x

3x+2y-12=0

3x+2y=12

3x+2(1+x)=12

3x+2+2x=12

3x+2x+2=12

5x=12-2

5x=10

x=10/5

x=2

x-y= -1

2-y= -1

-y= -1-2

-y= -3

y=3

hence,x=2 and y=3

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