I will surely mark your answer as brainliest...
Factorize:
x(x+y)³-3x²y(x+y)
Answers
Answered by
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Given : x(x + y)^3 - 3x^2y(x + y)
= > x(x + y)(x + y)(x + y) - 3x*xy(x + y)
= > x(x + y)[(x + y)(x + y) - 3xy]
= > x(x + y)[(x + y)^2 - 3xy]
= > x(x + y)[(x^2 + y^2 + 2xy - 3xy)]
= > x(x + y)(x^2 + y^2 - xy).
Hope this helps!
= > x(x + y)(x + y)(x + y) - 3x*xy(x + y)
= > x(x + y)[(x + y)(x + y) - 3xy]
= > x(x + y)[(x + y)^2 - 3xy]
= > x(x + y)[(x^2 + y^2 + 2xy - 3xy)]
= > x(x + y)(x^2 + y^2 - xy).
Hope this helps!
siddhartharao77:
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the procedure of taking equation from one side to other after changing its sign
the question is The procedure of taking one term of an equation from one side to other after changing its sign?
What is ur doubt
give me correct answer
please
I will ask to the user who has asked this question
is my answer correct or now @AK23..
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Answered by
1
ANSWER:-
= x(x+y) [ (x+y)²-3xy)
= x(x+y) (x²+y²)+xy -3xy
= x(x+y) (x²+y²-xy )
hope it will help u
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