Question

I will surely mark your answer as brainliest...
Factorize:
x(x+y)³-3x²y(x+y)

Answer 1

Given : x(x + y)^3 - 3x^2y(x + y)

= > x(x + y)(x + y)(x + y) - 3x*xy(x + y)

= > x(x + y)[(x + y)(x + y) - 3xy]

= > x(x + y)[(x + y)^2 - 3xy]

= > x(x + y)[(x^2 + y^2 + 2xy - 3xy)]

= > x(x + y)(x^2 + y^2 - xy).


Hope this helps!

Answer 2

ANSWER:-

= x(x+y) [ (x+y)²-3xy)

= x(x+y) (x²+y²)+xy -3xy

= x(x+y) (x²+y²-xy )

hope it will help u