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in cubic polynomial factorisation is done by assuming the factor of given polynomial which makes it 0.
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Answer:
(x+1)(2x+3)(2x-1)
Step-by-step explanation:
4x³+8x²+x-3
=4x³+4x²+4x²+x-3
=4x²(x+1) +4x²+4x-3x-3
=4x²(x+1) +4x(x+1)-3x(x+1)
=(x+1)(4x²+4x-3)
=(x+1)(4x²+6x-2x-3)
=(x+1) ( 2x(2x+3)-(2x+3) )
=(x+1)(2x+3)(2x-1)
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