Question

I will write a two digit number whose sum of the two numbers is 14 and subtracting 29 from the number will make the two numbers equal. Let's construct and solve the co-equation and see what will be the number of two digits?​

Answer 1

Answer:

Let the number be xy

Given x+y = 14

Also

10x+y - 29 = 10d+d —- Where d is some digit

10x + 14 -x - 29 = 11d

9x - 15 = 11d

9x = 11d + 15

Since LHS is a multiple of 9, RHS also should be. 15 leaves a remainder of 6 when dividing with 9. So 11d should leave a remainder of 3, the only such possibility is when d is 6.

So d=6, x =9, y = 5

Answer is 95

Please note we can also arrive at the solution by using trial and error using all permutations combinations of digits whose sum is 14. In this case (9,5),(8,6),(7,7)

Answer 2

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