I would like an explanation for kind of question please , I am not sure how to solve it .
please check the picture below . Thank you !
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Given for a Geometric progression
First term, b₁ = 1/9
Common ratio, q = 3
So, Tᵣ = b₁qʳ⁻¹
Let us suppose 243 be a term of the given sequence, so,
We must get r as a natural number if 243 is a term of the given sequence
Hence,
Tᵣ = 243 (Suppose)
or, 3⁻² × 3ʳ⁻¹ = 3⁵
or, 3ʳ⁻³ = 3⁵
or, r - 3 = 5
or, r = 8
Since, we get a natural number as the value of r
Hence, 243 is the 8th term of the given sequence.
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