Question

I write the 6th term of the arithmetic
sequence 1,25, 49,73,97...​

Answer 1

Step-by-step explanation:

given AP – 1, 25, 49, 73, 97,................

1st term = 1

2nd term = 25

d(difference) = 2nd term – 1st term

d = 25 – 1

d = 24

a(n)= a + (n–1)d

a(6) = 1 + (6–1)24

= 1 + (5)24

= 1 + 120

= 121

a(6) = 121

the 6th term of the given AP is 121