Question

(i) (x+1/x)^2-(x-1/x)^2​

Answer 1

Step-by-step explanation:

i hope this is helpful for you

Answer 2

Answer:

4

Step-by-step explanation:

Here given that

$(x+\frac{1}{x})^2-(x-\frac{1}{x})^2$ ............(1)

As we know the formula

$a^2-b^2=(a+b)(a-b)$

Using this formula in eq.(1), We get

$(x+\frac{1}{x})^2-(x-\frac{1}{x})^2=((x+\frac{1}{x})+(x-\frac{1}{x}))((x+\frac{1}{x})-(x-\frac{1}{x}))$

On solving

                               $=(x+\frac{1}{x}+x-\frac{1}{x})(x+\frac{1}{x}-x+\frac{1}{x})\\\\=(2x)(\frac{2}{x})\\ \\=4$