Question

(i) (x + 17) (x + 2)
(iv) (2 + 3x) (3 - 5x)
find the inspection the conefficient of X in the following expansion​

Answer 1

Step-by-step explanation:

$(x + 17)(x + 2) = 0 \\ x + 17 = 0 \: \: or \: \: x + 2 = 0 \\ x = - 17 \: \: or \: \: x = - 2$

$(2 + 3x)(3 - 5x) = 0 \\ 2 + 3x = 0 \: \: or \: \: 3 - 5x = 0 \\ 3x = 2 \: \: or \: \: - 5x = - 3 \\ x = \frac{3}{2} \: \: or \: \: x = \frac{3}{5}$

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Answer 2

Answer:

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