Math, asked by avrodipmondal92, 2 months ago


i) x^2+ 75 + p = 0 সমীকরণটির বীজদ্বয় যদি দুটি ক্রমিক অখণ্ড সংখ্যা হয়, তাহলে p-এর মান

Answers

Answered by areeq
0

Answer:

p = -75-x

Step-by-step explanation:

x2+75+p = 0

Or, x2+p = 0-75

Or, x2+p = -75

Or, x2/x + p/x = -75/x

Or, x+p/x = -75/x

Or, x+p = -75/x × x

Or, x+p = -75

Or, p = -75-x

(Ans)

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