i) x^2+ 75 + p = 0 সমীকরণটির বীজদ্বয় যদি দুটি ক্রমিক অখণ্ড সংখ্যা হয়, তাহলে p-এর মান
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Answer:
p = -75-x
Step-by-step explanation:
x2+75+p = 0
Or, x2+p = 0-75
Or, x2+p = -75
Or, x2/x + p/x = -75/x
Or, x+p/x = -75/x
Or, x+p = -75/x × x
Or, x+p = -75
Or, p = -75-x
(Ans)
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