(i) x + 2y + 1 = 0, 2x - 3y - 12 = 0
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Answer:
(3, -2)
Explanation:
x+2y+1=0
Multiply by 2,
2x+4y= -2_____(1)
2x-3y=12______(2)
Subtract (1) from (2)
7y= -14
y = -2
Substitute y = -2 in (1)
2x-8= -2
2x= -2 + 8
2x= 6
x=3
Therefore, (x,y) = (3, -2)
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