i) x+ 3y =7 and 2x + 3y =8 (Elimination Method)
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$$\begin{lgathered}\textsf{2x + 3y = 8 ---------------(1)}\\\textsf{x + 3y = 7-------------------(2)}\\\textsf{We will use substitution Method to solve this}\\\\\huge\textbf{But how?}\\\end{lgathered}$$
In Equation (2)
x + 3y = 7
x = 7- 3y
Now placing it in Equation (1)
2(7-3y)+3y = 8
14 - 6y +3y = 8
14 - 3y = 8
- 3y = -6
y = -6/-3
y = 2
Now placing y as 2 in Equation (2),
x + 3*2 = 7
x + 6 = 7
x = 1
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