i) x^8-1 factorise each of the following
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Answer:
(x2+1+2x)(x2+1−2x)(x2+1)(x+1)(x−1
Step-by-step explanation:
Given : x8−1
We can further write it as
x8−1=(x4)2−12
Based on the equation a2−b2=(a+b)(a−b)
We get,
x8−1=(x4+1)(x4−1)
x8−1=(x4+1)((x2)2−12)
x8−1=(x4+1)(x2+1)(x2−1)
So we get
x8−1=(x4+1)(x2+1)(x2−1)
By expanding the terms using the formula
We get,
x8−1=[(x2)2+12+2x2−2x2](x2−1)(x+1)(x−1)
On further simplification
x8−1=[((x2)2+12+2x2)−2x2](x2+1)(x+1)(x−1)
Using the formula we get
x8−1=(x2+1+2x)(x2+1−2x)(x2+1)(x+1)(x−1)
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