i) x+y=5 and 2x-3y=4 . solve the linear equation by the elimination method and the substitution method:
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Hey friend ..!! here's your answer
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x + y = 5 (1.)
2x - 3y = 4 (2.)
By substitute of eq 1. and 2
x = 5 -y (3.)
put the value of x in eq. 2
2(5- y) - 3y = 4
10 - 2y - 3y = 4
-5y = -6
y = 6/5
put value of y in eq. 3
x = 5 - 6/5
x = 25 - 6 / 5
x = 19/ 5
Now we solve the eq. 1 and 2 by using Elimination method.
x + y = 5 × 2
2x - 3y = 4 × 1
2x + 2y = 10
2x - 3y = 4
- + -
__________
5y = 6
y = 6/5
put value of y in eq. 1
x + y = 5
x = 5 - 6/5
x = 19 / 5
So that by solving equation 1 and 2 by using substitution and elimination method , we get the value :
x = 19/5
y = 6/5
_________________________
#Hope its help you dear#
☺
_________________________
x + y = 5 (1.)
2x - 3y = 4 (2.)
By substitute of eq 1. and 2
x = 5 -y (3.)
put the value of x in eq. 2
2(5- y) - 3y = 4
10 - 2y - 3y = 4
-5y = -6
y = 6/5
put value of y in eq. 3
x = 5 - 6/5
x = 25 - 6 / 5
x = 19/ 5
Now we solve the eq. 1 and 2 by using Elimination method.
x + y = 5 × 2
2x - 3y = 4 × 1
2x + 2y = 10
2x - 3y = 4
- + -
__________
5y = 6
y = 6/5
put value of y in eq. 1
x + y = 5
x = 5 - 6/5
x = 19 / 5
So that by solving equation 1 and 2 by using substitution and elimination method , we get the value :
x = 19/5
y = 6/5
_________________________
#Hope its help you dear#
☺
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