Math, asked by xyz123a, 5 months ago

(i) (x + y) and (x^2 – xy + y^2)

please fast​

Answers

Answered by Anonymous
3

Step-by-step explanation:

(x+y)(x

(x+y)(x 2

(x+y)(x 2 −xy+y

(x+y)(x 2 −xy+y 2

(x+y)(x 2 −xy+y 2 )

(x+y)(x 2 −xy+y 2 )=x(x

(x+y)(x 2 −xy+y 2 )=x(x 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y −

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3 +y

(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3 +y 3

Answered by Anonymous
1

(x+y)(x

2

−xy+y

2

)

=x(x

2

−xy+y

2

)+y(x

2

−xy+y

2

)

=x

3

−x

2

y+xy

2 +x

2 y − xy

2 +y 3=x

3 +y 3

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