(i) (x + y) and (x^2 – xy + y^2)
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Answers
Step-by-step explanation:
(x+y)(x
(x+y)(x 2
(x+y)(x 2 −xy+y
(x+y)(x 2 −xy+y 2
(x+y)(x 2 −xy+y 2 )
(x+y)(x 2 −xy+y 2 )=x(x
(x+y)(x 2 −xy+y 2 )=x(x 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y −
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3 +y
(x+y)(x 2 −xy+y 2 )=x(x 2 −xy+y 2 )+y(x 2 −xy+y 2 )=x 3 −x 2 y+xy 2 +x 2 y − xy 2 +y 3 =x 3 +y 3
(x+y)(x
2
−xy+y
2
)
=x(x
2
−xy+y
2
)+y(x
2
−xy+y
2
)
=x
3
−x
2
y+xy
2 +x
2 y − xy
2 +y 3=x
3 +y 3