Question

I)x×z<y×z









ii)4x-3y=16;6x+5y=62​

Answer 1

Answer:

what is your question.plz post complete question

Answer 2

Answer:

{x,y}={6,4}

Step-by-step explanation:

// solve equation [2] for the variable x

[2] 4x = 3y + 12

[2] x = 3y/ 4+3

// plug this in for variable x in equation [1]

[1] 6. (3y/ 4+3)-5y=16

[1] -Y/2=-2

[1] -y=-4

// solve equation [1] for the variable y

[1] y=4

// by now we know this much :

x= 3y/4+3

y=4

// use the y value to solve for x

x = (3/4)(4)+3=6

solutions :

{x,y}={6,4}

Hope it helps you.

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