Question

I. x2 + 14x + 45 = 0

II. 2y2 + 5y – 25 = 0
A . x > y
B x < y
C x ≥ y
D x ≤ y
E x = y or relationship between x and y can't be established

Answer 1

Answer:

 option D .x ≤ y

Step-by-step explanation:

I. x2 + 14x + 45 = 0

x2 + 5x + 9x + 45 = 0

x(x + 5) + 9(x + 5) = 0

(x + 9)(x + 5) = 0

x = –9, –5

II. 2y2 + 5y – 25 = 0

2y2 + 10y – 5y – 25 = 0

2y(y + 5) –  5(y + 5) = 0

(2y – 5)(y + 5) = 0

y = 2.5, –5

For x = –5 and y = –5

x = y

For x = – 9 or – 5 and y = 2.5

x < y

For x = –9 and y = –5

x < y

Therefore, x ≤ y

Hence, option D is correct.

if you like my ans please thanks and support

Answer 2

Answer:

x= -9 & x= -5

y= -5 & y= -5/2

answer is D x≤ y