Question

(i) x2 – 2x -8 find the zeros of the polynomial and verify the relationship between the zeros and the cofficients.​

Answer 1

Answer:

Step-by-step explanation:

P(x) = x²-2x

Zeroes of p(x) ,

P(x) = x(x-2)

∴ x = 0 or x = 2

Relationship between Coefficient and zeros of P(x)

Sum of zeroes = -b/a = -(-2)/1

⇒ sum = 2

product of Zeroes = c/a = 0 / 1 ⇒ 0

Adding the zeroes = 2+0 = 2

Product = 2x0 = 0

Thus, verified.