Question

(i) x2 - 2x - 8. relationship between zeros and coefficient in quadratic polynomial
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Answer 1

Answer:

$\huge\mathcal{\purple{answer}}$

Step-by-step explanation:

P(x)=x²-2x-8

=x²-2x+4x-8=0

= x(x-2)+4(x-2)=0

= (x-2)(x+4)=0

x=2 x=-4

So,

$\alpha = 2 \: \: \: \: \beta = - 4$

Therefore zeros are 2 and-4

$sum \: of \: zeroes = \alpha + \beta \\ = 2 + ( - 4) \\= - 2$

$product \: of \: zeroes = \alpha \times \beta \\ = 2 \times ( - 4) \\ = - 8$