Question

I you solve this question properly with process. I will surely f.o.l.l.o.w you and l.i.k.e all your answer. Make it fast please​

Answer 1

Answer:

hey here is your answer

so pls mark it as brainliest

Step-by-step explanation:

now here

15/x+y+7/x-y=10 can be represented as

15×1/x+y+7×1/x-y=10

similarly 5/x+y-2/x-y=-1 can be represented as

5×1/x+y-2×1/x-y=-1

so let 1/x+y=m and 1/x-y=n

thus then we get

15m+7n=10 (1)

5m-2n=-1 (2)

so multiplying (2) by 3

we get

15m-6n=-3 (3)

so subtracting (3) from (1)

we get

13n=13

ie n=1

substitute value of n in any of three equations

we get

m=1/5

so resubstituting values of m and n as 1/x+y and

1/x-y respectively

we get

1/x+y=1/5 & 1/x-y=1

ie x+y=5 (4)

x-y=1 (5)

adding (4) and (5)

we get

2x=6

ie x=3

substitute value of x in (4)

we get

y=2

thus (x,y)=(3,2) is solution of above linear equations