Chemistry, asked by priyanshusingla, 1 year ago

I2 +NaoH (hot and concentrated)

Answers

Answered by Anonymous

1

Cl2 + 2 NaOH ==> NaCl + NaOCl + H2O for cold NaOH

3 Cl2 + 6 NaOH ==> 5 NaCl + NaClO3 + 3 H2O for hot NaOH

Chlorine is oxidized much more strongly with hot NaOH than cold

Cl2 starts neutral and becomes +1 in NaOCl

Cl2 starts neutral and becomes +5 in NaClO3

the heat and concentrated NaOH are stronger oxidizing agents than cold dilute NaOH

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