Question

I2 (s) to I2 (g) ; ΔH = + 40 kcal, ΔS = 80 cal. The sublimation point of I2 (s) will be​

Answer 1

Explanation:

Enthalpy of Fusion :- It is the enthalpy change accompanied by melting of one mole of solid substance.

Enthalpy of Vapourisation :- It is the enthalpy change accompanied by conversion of one mole of liquid substance completely into vapours.

Enthalpy of Sublimation :- It is the enthalpy charge when one mole of a solid substance sublimes.

Enthalpy of sublimation of I

2

(s) = Enthalpy of fusion of I

2

+ Enthalpy of vaparization of I

2

∴57.3=15.5+ Enthalpy of vaparization of I

2

∴ Enthalpy of vapourization of I

2

=57.3−15.5=41.8KJ/mol