Math, asked by abhiraje750, 8 months ago

i³⁷+1÷i⁶⁷ evaluate the following​

Answers

Answered by sandy1816
2

Step-by-step explanation:

i^37+1/i^67

=(i^4)^9.i+1/(i^4)^16.i^3

=i+1/-i

=(1+i)i/-i.i

=i+i²/-i²

=i-1/(-1)²

=-1+i

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