i4o9 is a/an :
(A) Ionic compound
. (B) Covalent compound
(C) Coordinate compound
(D) Double salt
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Answer:
(A)ionic compound
Explanation:
I4O9 is actually nothing but I(IO3)3 which gets ionised
I(IO3)3 ⇋I^3+ + 3(IO3)^-
so, that is an ionic compound
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