i⁷ + i⁹ + i¹¹ + i¹³ = ?
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6
Answer:
0
Step-by-step explanation:
⇒ i^7 + i^9 + i^11 + i^13
⇒ i^( 8 - 1 ) + i^( 8 + 1 ) + i^( 12 - 1 ) + i^( 12 + 1 )
⇒ ( i^8 * i^(-1) ) + ( i^8 * i^1 ) + ( i^12 * i^(-1) ) + ( i^12 * i^(-1) )
⇒ ( 1 * i^(-1) ) + ( 1 * i^1 ) + ( 1 * i^(-1) ) + ( 1 * i^(-1) )
⇒ i^(-1) + i^(1) + i^*(-1) + i^(1)
⇒ 2( i^(-1) + i )
⇒ 2( - i + i )
⇒ 2( 0 )
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Answer:
Refer to the attachment given ☝️
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