Question

( i77 + i82 + i87 + i92.
ka mapank gyeyat kegye
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Answer 1

Answer:

i^77 + i^82 + i^87 + i^92

here i is unit of imaginary number

hence, i^2 = -1 and i^4 = 1

now,

i*(i^4)^19 + i^2*(i^4)^20 + (i^4)^23

= i + i^2 = 1

= I - 1 + 1

= i