Math, asked by S16914Aditi, 8 months ago

IA square park of side 80 m, there is a swimming pool
measuring 25 m x 20 m. The rest is picnic ground as shown in
fig-7. What is the area of picnic ground?

Answers

Answered by Anonymous
45

\mathfrak{\huge{\green{\underline{Given:-}}}}

Side of the square park = 80 m

Length of the swimming pool = 25 m

Breadth of the swimming pool = 20 m

\mathfrak{\huge{\green{\underline{To \: Find:-}}}}

The area of the picnic ground.

\mathfrak{\huge{\green{\underline{Analysis:-}}}}

Find the area of the swimming pool and the square park, then subtract the area of the area of swimming pool from the area of the square park in order to get the area of the picnic ground.

\mathfrak{\huge{\green{\underline{Solution:-}}}}

Area of the swimming pool = Length × Breadth

\implies \sf 25 \times 20

\implies \sf 500 \: m^{2}

Area of the square park = Side × Side

\implies \sf 80 \times 80

\implies \sf 6400 \: m^{2}

Area of the picnic ground = Area of square park − Area of swimming pool

\implies \sf 6400-500

\implies \sf 5900 \: m^{2}

Therefore, the area of the picnic ground is 5900 m²

\mathfrak{\huge{\green{\underline{Points \: to \: Note:-}}}}

Area measures the space inside a shape.

Formula of area of rectangle is Length × Breadth.

Formula of area of square is Side × Side.

Answered by TheValkyrie
4

Answer:

\bigstar{\bold{Area\:of\:picnic\:ground\:=5900\:m^{2} }}

Step-by-step explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • Length of side of square park = 80 m
  • Length of swimming pool = 25 m
  • Breadth of swimming pool = 20 m

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • Area of picnic ground

\Large{\underline{\underline{\bf{Solution:}}}}

→ As given in the attatchment

  Area of picnic ground = Area of park - Area of pool-----equation 1

Area of square park = side × side

→ Substituting the data we get,

  Area of square park = 80 × 80 = 6400 m²--------equation 2

Area of rectangular pool =  Length × Breadth

→ Substituting the values we get,

  Area of pool = 25 × 20 = 500 m²------equation 3

→ Substituting equation 3 and equation 2 in equatio 1 we get,

   Area of picnic ground = 6400 - 500

\boxed{\bold{Area\:of\:picnic\:ground\:=\:5900\:m^{2} }}

\Large{\underline{\underline{\bf{Notes:}}}}

→ Perimeter of a square = 4a

→ Area of a square = a²

→ Perimeter of a rectangle = 2(l + b)

→ Area of a rectangle = l × b

,

 

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