Question

iaka ka nas bolo please kal exam h

Answer 1

$\bold\underline{ANSWER}$

$F = \frac{G \: m1 \: m2 \: }{ {r}^{2} } \\ \\ when \: the \: distance \: is \: reduced \\ \: to \: \: half \\ \\ F \: = \frac{G \: m1 \: m2 \: }{ { (\frac{1}{2}) }^{2} } \\ \\ F = \frac{G \: m1 \: m2 \: }{ \frac{1}{4} } \\ \\ = > 4F \: = G \: m1 \: m2$

Here F denotes force of attraction G denotes gravitational force M denotes masses of the bodies and R denotes the distance between them.

So the force of gravitation becomes four times when the distance is reduced to half.

Answer 2

Answer:

bold\underline{ANSWER}

\begin{gathered}F = \frac{G \: m1 \: m2 \: }{ {r}^{2} } \\ \\ when \: the \: distance \: is \: reduced \\ \: to \: \: half \\ \\ F \: = \frac{G \: m1 \: m2 \: }{ { (\frac{1}{2}) }^{2} } \\ \\ F = \frac{G \: m1 \: m2 \: }{ \frac{1}{4} } \\ \\ = > 4F \: = G \: m1 \: m2\end{gathered}

F=

r

2

Gm1m2

whenthedistanceisreduced

tohalf

F=

(

2

1

)

2

Gm1m2

F=

4

1

Gm1m2

=>4F=Gm1m2

Here F denotes force of attraction G denotes gravitational force M denotes masses of the bodies and R denotes the distance between them.

So the force of gravitation becomes four times when the distance is reduced to half.