Iam going to appear for board please can you hurry up solve1and 3
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U can solve second one by converting tan into sin/cos and then taking sin common and cancelled b/w numerator and denominator IN THE LHS
U can solve second one by converting tan into sin/cos and then taking sin common and cancelled b/w numerator and denominator IN THE LHS
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where is half
now done?
we need 1/sec A-tan A not 1/secA-tanA
rhs should 1/cosA-1/(secA-tan A ) help me
thanks for trying
are yo kidding
how can we find 1/cos-1/sin-tan without changing the -ve sign
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