IAS question - ❓❓❓❓❓❓
A man starts frm his house with some money to visit four temples.
1. As soon as he enters temple 1 his money gets doubled. He donates 100 rs nd moves.
2. At temple 2 again his money is doubled and he donates 100 rs.
3. His money is doubled again at temple 3 and he donates 100 rs.
4. At temple 4 again his money gets doubled. He donates 100 rs. again and returns home empty handed.
How much money he had when he started from his house???
This is a challenge for all the masterminds...
Answers
Let the amount the man initially had be x...
When he reached the first temple, the money doubled...
So, the amount now is 2x...
He donates 100...
So, balance amount = 2x – 100
This again doubles at 2nd temple...
So, he has 2 (2x - 100) => 4x – 200
He gives 100...
So, he has 4x – 200 – 100 = 4x – 300
It doubles and he has 2(4x - 300) = 8x – 600
He gives 100...
So, he has 8x – 700
Thus, he has 2(8x - 700) = 16x – 1400
He gives 100 and has nothing. Thus 16x – 1400 – 100 = 0
- => 16x – 1500 = 0
- => 16x = 1500
- x = 1500/16
- = 93.75
Thus, he started from home with Rs.93.75...
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Thanks!!...❣️✌️
He initially had 93.75 rupees with him.
Initially, let us say, he had 'x' rupees.
He visited 4 temples overall.
Before visiting every temple, his money got doubled. In every temple, he offered 100 rupees.
At first temple:
The money got doubled = 2x
He offered 100 from the money he had = 2x - 100
At second temple:
Again, the money got doubled = 2(2x-100) = 4x - 200
Offered 100 at second temple = 4x - 200 - 100 = 4x - 300
At third temple:
The money got doubled = 2(4x-300) = 8x - 600
He offered 100 from the money he has = 8x - 600 - 100 = 8x - 700
At fourth temple:
Again, the money got doubled = 2(8x-700) = 16x - 1400
Offered 100 at fourth temple = 16x - 1400 - 100 = 16x - 1500
It is said that, after offering at fourth temple, he has no money left with him.
So, the equation becomes 16x - 1500 = 0
16x = 1500
x = 1500/16
x = 93.75
Therefore, he initially had 93.75 rupees with him.
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