ib
3
much of NaOH required
neutrilised 150 och at
NHCl (Na-23)
options @ Yag (g
6 Yg (c) Gg (Joog
Answers
Answered by
0
Answer:
Solution:- (C) 3:1
Let x and y be the fraction of
17
35
Cl and
17
37
Cl in
17
35.5
Cl.
Therefore,
Average at. mass =
x+y
x×35+y×37
35.5=
x+y
35x+37y
⇒35.5x+35.5y=35x+37y
⇒35.5x−35x=37y−35.5y
⇒0.5x=1.5y
⇒
y
x
=
0.5
1.5
=
1
3
Hence the ratio of
17
35
Cl and
17
37
Cl in
17
35.5
Cl is 3:1.
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