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A bag contains 4 black, 5 yellow and 6 green balls. Three balls are drawn at random from the bag. What is the probability that all of them are yellow?
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Let the event be P(E)
no.of favorable outcomes (yellow) = 5
Total no.of possible outomes = 4+5+6 = 15
P(E) = no.of favorable outcomes/ total no.of possible outcomes
P(E) = 5/15
P(E) = 1/3
therefore, probability of getting yellow ball from bag is 1/3
no.of favorable outcomes (yellow) = 5
Total no.of possible outomes = 4+5+6 = 15
P(E) = no.of favorable outcomes/ total no.of possible outcomes
P(E) = 5/15
P(E) = 1/3
therefore, probability of getting yellow ball from bag is 1/3
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