Question

IB exams

A body is thrown vertically upward
and it reaches 10m high. Find the velocity with which the body was thrown? (g =
9.8 m/s)

Answer 1

$H_{max}=10\\\\v= \sqrt{2gh}= \sqrt{2 \times 9.8 \times 10}= \sqrt{196}=14\ m/s$

SO it was thrown at 14 m/s.

Answer 2

Answer:

Maximum height h = 10 m/s At maximum height, v = 0 Let the initial velocity be u .Acceleration a = - g = - 9.8 m/s2 0 - u2 = 2( - 9.8)(h) u = √(2gh) ...

Top answer

Maximum height h = 10 m/s At maximum height, v = 0 Let the initial velocity be u .Acceleration a = - g = - 9.8 m/s2 0 - u2 = 2( - 9.8)(h) u = √(2gh) ...