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The length of a rectangle is twice its breadth. If its length is decreased by 5 cm and breadth is increased by 5 cm, the area of the rectangle is increased by 75 sq.cm. What is the length of the rectangle?
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Answered by
1
let the breadth of the given rectangle be x then length is 2x.
thus area of the given rect is 2x^2
after dec 5cm from length and inc 5cm breadth
new lenght becomes 2x-5
and breadth is x+5
thus new area =(2x-5)(x+5)
=2x^2-5x+10x-25
=2x^2+5x-25
since new area is 75 units greater than original area thus
2x^2+75=2x^2+5x-25
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
thus area of the given rect is 2x^2
after dec 5cm from length and inc 5cm breadth
new lenght becomes 2x-5
and breadth is x+5
thus new area =(2x-5)(x+5)
=2x^2-5x+10x-25
=2x^2+5x-25
since new area is 75 units greater than original area thus
2x^2+75=2x^2+5x-25
5x=75+25
5x=100
therefore x=20
hence length of the rectangle is 40 cm.
Answered by
4
rectangle length = L and breadth = B.
L = 2 B and Area = LB = 2 B²
new length L' = L - 5 cm = 2 B - 5 cm
new breadth B' = B + 5 cm
New Area of rectangle = L' B'
= (2B - 5) (B + 5)
= 2 B² + 10 B - 5 B - 25
Increase in the area = L'B' - L B = 5 B - 25
= 75 cm²
=> B = (75+25)/5 = 20 cm
=> L = 2 B = 40 cm
L = 2 B and Area = LB = 2 B²
new length L' = L - 5 cm = 2 B - 5 cm
new breadth B' = B + 5 cm
New Area of rectangle = L' B'
= (2B - 5) (B + 5)
= 2 B² + 10 B - 5 B - 25
Increase in the area = L'B' - L B = 5 B - 25
= 75 cm²
=> B = (75+25)/5 = 20 cm
=> L = 2 B = 40 cm
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