Question

Ib the adjoining figure,AP is a man of height 1.8m and PQ is a building 13.8m high. If the man sees the top of the building by focusing his binoculars at 30° to horizontal. Find the distance of the man and the building.

Answer 1

According to the given formula

$\frac{1}{ \sqrt{3 } } = \frac{13.8 - 1.8}{d}$
By cross multiplication

$d = 12 \sqrt{3 }$
or
$d = 20.7846m$