Question

IBr7 cannot exist but IF7 exist ,This fact can be explained on the basis of

Answer 1

Answer:

The existence of IF7 and non-existence of IBr7 can be explained on the basis of electronegativity and the size of atoms. - Fluorine is the most electronegative element in the periodic table. ... - Due to this, it can form 7 bonds with iodine very easily and form IF7.

Answer 2

Answer:

On the basis of electronegativity and atom size, the existence of $IF_7$ and the absence of $IBr_7$ can be explained.

Explanation:

• We know that Fluorine is the most electronegative element present in the periodic table. As a result, Fluorine just requires one electron to occupy its outermost shell and achieve stability.
• As a result of the Noble gases configuration of Iodine, Fluorine can form a bond. However, Chlorine and Bromine are not sufficiently electronegative to achieve that level of stability and establish a stable bond with Iodine's noble gas structure. Thus, we can see that $IBr_7$ can't exist but $IF_7$ exist.