ic a pair of dice is thrown
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The easiest way to do this is to compute the opposite probability - the probability that you throw two dice and get no 5’s. We can then subtract this from 1 to get our answer.
The probability of throwing one die and not getting a 5 is [math]\frac{5}{6[/math]}.
So the probability of throwing two dice and not getting a 5 is .
Subtracting from from 1 gives the probability you are looking for: .
hope it help
The probability of throwing one die and not getting a 5 is [math]\frac{5}{6[/math]}.
So the probability of throwing two dice and not getting a 5 is .
Subtracting from from 1 gives the probability you are looking for: .
hope it help
Answered by
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Answer:
Then there are 6 outcomes.
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