Question

Ice at 0 degrees celsius is added to 200g of water initially at 70 degree celsius in a vacuum flask when 50g of ice has been added and has all melted the temperature

Answer 1

The final temperature is equal to 40°C.

Let T be the final temperature.

Specific heat of water = 1 cal/gm

Latent heat of fusion = L = 80 cal/gm

When the ice is added to the water at 70°C ,then the ice completely melts . The melted ice with the water will reach at an equilibrium temperature .

At equilibrium -

Amount of heat lost = amount of heat gained

=> m1 × s × (70 -T) = m2L + m2 × s × (T-0)

=> 200 × 1 × (70-T) = 50 × 80 + 50 × 1 × (T)

=> 14000 - 200T = 4000 + 50T

=> 250T = 10000

=> T= 40°C

The final temperature is equal to 40 °C.

Answer 2

Answer:

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