Question

ice cube of edge length 2 cm slides with the momentum of 500 grams second -1 what is the its velocity​

Answer 1

Given:

Ice cube of edge length 2cm slides with a momentum equal to 500 g m/s.

To find:

Velocity of ice cube.

Calculation:

Volume of ice cube:

$vol. = l \times l \times l$

$= > vol. = {(0.02)}^{3}$

$= > vol. = 8 \times {10}^{ - 6} \: {m}^{3}$

Mass of ice cube:

$mass = density \times vol.$

$= > mass = 1000 \times (8 \times {10}^{ - 6} )$

$= > mass =8 \times {10}^{ - 3} kg$

$= > mass =8 \: gm$

Now, let velocity be v.

$momentum = mass \times velocity$

$= > 500 =8 \times velocity$

$= > velocity = \dfrac{500}{8}$

$= > velocity = 62.5 \: m {s}^{ - 1}$

So, final answer is:

$\boxed{ \bold{ velocity = 62.5 \: m {s}^{ - 1}}}$

Answer 2

Answer:

given = edge length of ice cube = 2 cm

         mementum = 500 grams second⁻¹

to find = velocity = ?

solution =

to find the velocity we have to find the mass and volume of cube so,

volume of ice cube =  l³

2 ×2×2 = 8  

           = 8 × 10  ⁻⁶  m³

mass of the cube =   density × volume

                             =   1000 × 8 ×10 ⁻⁶

now velocity ,=

                     =  mementum / mass

                     =      500 / 8

                 =    62.5 ms⁻¹