Question

Ice of water at 100°C is given 540 cal of
heat and the steam formed occupies 1671cc
at 1 atm pressure. Then workdone against
atmospheric pressure in this process is
nearly
1) 540 cal 2) 500 cal 3) 40 cal 4) 100 cal​

Answer 1

Explanation:

work done against atmospheric pressure

= 1671*10^-6 * 10^5 = 169 J = 40 cal

option 3 is correct