ICH2CH2Cl+NaI IN DRY ACETONE GIVES WHAT PRODUCT PLZZZ ANSWER FAST AND CORRECTLY
COREECT ANSWERS WILL BE MARKED BRAINLIEST BUT EXPLANATION IS REQUIRED*
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Answer:
The result is that sodium chloride crystallizes out of solution, and the Finkelstein reaction proceeds to completion! Acetone. NaI in spacefill mode.
Explanation:
R − C l + N a + I − → R − I + N a C l ↓
Because sodium iodide is much more soluble than sodium chloride in acetone, when you do this you see a glassy precipitate of sodium chloride in the acetone. I think there is a named organic spot test for this reaction (its name escapes me at the moment, I should not have finished that bottle of wine last night!). If you have time in an organic laboratory it would be worth your while to do this reaction in a small test tube so you can notice the turbidity of the sodium chloride when it precipitates.
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