Chemistry, asked by shivanshway, 10 months ago

ICH2CH2Cl+NaI IN DRY ACETONE GIVES WHAT PRODUCT PLZZZ ANSWER FAST AND CORRECTLY

COREECT ANSWERS WILL BE MARKED BRAINLIEST BUT EXPLANATION IS REQUIRED*

Answers

Answered by senikale278
0

Answer:

The result is that sodium chloride crystallizes out of solution, and the Finkelstein reaction proceeds to completion! Acetone. NaI in spacefill mode.

Explanation:

R − C l + N a + I −  →   R − I + N a C l ↓  

Because sodium iodide is much more soluble than sodium chloride in acetone, when you do this you see a glassy precipitate of sodium chloride in the acetone. I think there is a named organic spot test for this reaction (its name escapes me at the moment, I should not have finished that bottle of wine last night!). If you have time in an organic laboratory it would be worth your while to do this reaction in a small test tube so you can notice the turbidity of the sodium chloride when it precipitates.

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