id 2k+1 4k+3 and 8k+1 are three consecutive terms of an ap find the value of k and 18 th term of the sequence
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Let, a = 2k + 1, b = 4k + 3 & c = 8k + 1
» 2b = a + c
» 8k + 6 = 2k + 1 + 8k + 1
» 2k = 4
» k = 2
Therefore, k = 2
» t1 = 5 & t2 = 11
» d = 6
» t18 = a + 17d
= 5 + 102 = 107
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