Id a+b+c = 0, prove that a^2/bc + b^2/ab + c^2/ca = 3
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Answer:
acube+bcube+ccube=3abc
Step-by-step explanation:
if a+b+c=0 so acube+bcube+ccube=3abc
a^2/bc +b^2/cb+c^2/ca= a^3+b^3+c^3/abc= 3abc/abc
=3
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