Question

Ida=13,b=14and c=15,then the circumradius is

Answer 1

Answer:

Semi-perimeter of the triangle s = (a+b+c)/2 = (13+14+15)/2 = 21;

Area of the triangle A = [s(s-a)(s-b)(s-c)]^0.5 = [21*8*7*6]^0.5 =84 (using Heron’s Formula);

Circumradius of the triangle = (abc)/(4*A) = (13*14*15)/(4*84) = 65/8.