Physics, asked by satyen0707, 11 months ago

Ideal gas at pressure P undergoes free expansion
from its initial volume of 1.01 Litre to 10.1 Litre.
The final pressure of the gas is?
P
(1) P(10)y (2)
(3) 10P
(4)
107
10​

Answers

Answered by NikhilSinghNS630
2

Answer:

be to look b do if ki c go back in 5680000000^^^54855

Answered by jeetbhatt05359
7

Answer:(4) P/10

Explanation:Free expansion - expansion under vacuum at adiabatic conditions.

So in adiabatic process Q=0 and in vaccum W=0

So from first law of thermodynamics (FLOT)

Q=U+W

=>Delta U =Q-W

=>Delta U=0

n×Cv×deltaT=0

n and Cv can't be 0 so deltaT is 0 thus temperature is const

Therefore'from ideal gas equation PV=nRT

Thus, PV=Constant

P'=(PV)/V'

P'= (P×1.01)/10.1

P'=P/10

Hence 4th option is correct.

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