Ideal gas at pressure P undergoes free expansion
from its initial volume of 1.01 Litre to 10.1 Litre.
The final pressure of the gas is?
P
(1) P(10)y (2)
(3) 10P
(4)
107
10
Answers
Answered by
2
Answer:
be to look b do if ki c go back in 5680000000^^^54855
Answered by
7
Answer:(4) P/10
Explanation:Free expansion - expansion under vacuum at adiabatic conditions.
So in adiabatic process Q=0 and in vaccum W=0
So from first law of thermodynamics (FLOT)
Q=U+W
=>Delta U =Q-W
=>Delta U=0
n×Cv×deltaT=0
n and Cv can't be 0 so deltaT is 0 thus temperature is const
Therefore'from ideal gas equation PV=nRT
Thus, PV=Constant
P'=(PV)/V'
P'= (P×1.01)/10.1
P'=P/10
Hence 4th option is correct.
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