Question

ideal gas equation for 7g of Oxygen gas can be represented as ________________ *

a)PV = 7RT
b) PV = (32/7)RT
c) PV = (7/32)RT
d) PV = 32RT​

Answer 1

As we know the relation of Ideal Gas Equation :-

PV = nRT

P is the Pressure.

V is Volume.

R is Gas constant.

T is Temperature.

n is Moles.

Now, coming to the question,

PV = given mass/Molar Mass × RT

PV = (7/32)RT.

This is the correct option.

Answer 2

Given that , Mass of Oxygen is 7 g .

Exigency To Find : Ideal gas equation for 7g of Oxygen gas can be represented as ?

⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

⠀⠀⠀⠀⠀¤ Firstly we should know Ideal Gas Equation :

$\dag\:\:\pmb{ As,\:We\:know\:that\::}\\\\\qquad\maltese\:\:\bf \:Ideal \: gas \: Equation \::$

$\qquad \dag\:\:\bigg\lgroup \pmb{\sf{ \:\:\: PV \:\:=\:\:nRT \qquad }}\bigg\rgroup$

⠀⠀⠀⠀⠀Where ,

• P is the Pressure of ideal gas .
• n is theamount of ideal in number of moles .
• R is the gas constant .
• T is the Temperature
• V is the Volume of ideal gas .

As , We know that ,

$\qquad \dag\:\:\bigg\lgroup \pmb{\sf{ \:\:\: Number \:of \:moles \:(\:or \:n\:)\:= \: \dfrac{ Mass }{Molar \:mass } \qquad }}\bigg\rgroup$

⠀⠀⠀⠀⠀⠀⠀Here , Mass of the oxygen is 7 g & Molar mass of Oxygen or $\bf O_2$ is 32 .

$\qquad \dashrightarrow \sf \:\:\: PV \:\:=\:\:nRT \qquad$

$\qquad \dashrightarrow \sf \:\:\: PV \:\:=\:\:\bigg(\:\dfrac{ Mass }{Molar \:mass }\:\bigg) RT \qquad$

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \dashrightarrow \sf \:\:\: PV \:\:=\:\:\bigg(\:\dfrac{ Mass }{Molar \:mass }\:\bigg) RT \qquad$

$\qquad \dashrightarrow \sf \:\:\: PV \:\:=\:\:\bigg(\:\dfrac{ 7 }{32 }\:\bigg) RT \qquad$

$\qquad \therefore \pmb{\underline{\purple{\frak{\:\:\:\: PV \:\:=\:\:\bigg(\:\dfrac{ 7 }{32 }\:\bigg) RT \: }}} }\:\:\bigstar$

⠀⠀$\qquad \therefore \:\underline {\sf\: Hence\:, \:Ideal \:gas \:\:Equation \:for \:7g \:of \:\:Oxygen\:can \: be \:represented\:as\: \bf PV \:=\:\:\:\bigg(\:\dfrac{ 7 }{32 }\:\bigg) RT \:} \:$