Question

ideal gas equation in terms of KE per unit volume ,E is​

Answer 1

Answer:

do with your my freind dont said to another freind

Answer 2

Explanation:

as we know...

PV = 1/3mv²NA

PV = 1/3mv²NA3PV = mv²NA......(1)

divide the equation 1by 2

3/2PV = 1/2mv²NA

3/2PV = 1/2mv²NA3/2 PV = KEof molecule

3/2PV = 1/2mv²NA3/2 PV = KEof molecule3/2P = KE/V

3/2PV = 1/2mv²NA3/2 PV = KEof molecule3/2P = KE/V3/2 P = Kinetic energy per unit volume

P = 2/3*Kinetic energy per unit volume

Ideal gas equation.....

PV = nRT.....(2)

now put value of P in equ. (2)

2/3*Kinetic energy per unit volume*V

2/3*Kinetic energy per unit volume*V = n RT

2/3*Kinetic energy per unit volume*V = n RT2/3*KE*V/V= nRT

2/3*KE = nRT