Ideal gas of mass m follows a process from state p,2v to 2p,v what is the maximum/minimum temperatyre
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Hey mate,
# Answer - Maximum temperature/Minimum temperature = 1
# Explanation-
For an ideal gas,
PV = nRT
Initially, i.e at condition (2P,V)
2P.V = nRTi ...(1)
Finally, i.e at (P,2V)
P.2V = nRTf ...(2)
Dividing (1) by (2)
Ti = Tf
Hence, No change in temperature. It is isothermal process.
(I'll solve further,
As internal energy is directly proportional to temperature, it is zero for an isothermal process.
ΔU = 0
Now, first law of thermodynamics,
ΔU = Q - W
0 = Q-W
Q = W
Hence, Heat absorbed is equal to work done. )
Hope you understand clearly...
# Answer - Maximum temperature/Minimum temperature = 1
# Explanation-
For an ideal gas,
PV = nRT
Initially, i.e at condition (2P,V)
2P.V = nRTi ...(1)
Finally, i.e at (P,2V)
P.2V = nRTf ...(2)
Dividing (1) by (2)
Ti = Tf
Hence, No change in temperature. It is isothermal process.
(I'll solve further,
As internal energy is directly proportional to temperature, it is zero for an isothermal process.
ΔU = 0
Now, first law of thermodynamics,
ΔU = Q - W
0 = Q-W
Q = W
Hence, Heat absorbed is equal to work done. )
Hope you understand clearly...
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