Question

Identify ‘A’ in the following reaction:
CH3COOH + Na2CO3 → A + CO2 + H0O
(a) CH3COONa
(b) CH2(Na)COOH
(c) NaOH
(d) NaHCO3

Answer 1

Answer:

Na2CO3 + 2CH3COOH = 2CH3COONa + CO2 + H2O

Explanation:

As there is sodium bicarbonate and a compound . So product should have equal number of atoms as of reactant and so verifying the law of conservation of mass.

Answer 2

A is (a) CH3COONa in the given reaction.

• The given reaction is an example of a neutralization reaction.
• Ethanoic acid (CH₃COOH) reacts with sodium carbonate (Na₂CO₃) to form a salt.
• Carbon dioxide (CO₂) and water (H₂O) are also released as by-products in the reaction.
• The salt produced is a sodium salt of acetic acid called sodium acetate. It has the formula CH₃COO⁻Na⁺.
• The negative charge of the acetate ions is neutralized by the positive charge on the sodium ions.